The thickness of an aluminum plate with a thickness of 1/8 inch is approximately 0.125 inches, which is equal to 3.175 millimeters. The 1/8 aluminum plate weight is equal to the area multiplied by the thickness and density. If the weight is required in kilograms, the length unit is converted to decimeters. For example, for a 1 square meter aluminum plate, the area is equal to 100 square decimeters. A thickness of 1/8 inch aluminum plate is 3.175 millimeters is equal to 0.03175 decimeters. The density of aluminum is assumed to be 2.7 kilograms per cubic decimeter. Therefore, the weight is equal to 100 multiplied by 0.03175 multiplied by 2.7, which is equal to 8.58 kilograms. In other words, a 3 millimeter thick aluminum plate weighs 8.58 kilograms per square meter.
For alloy aluminum plates, the density is between 2.7 and 2.9g/cm2. Here, we take 2.8g/cm2 as an example to calculate the weight of a 1/8 aluminum plate. The formula is as follows: 1/8 aluminum plate weight = Area x Thickness x Density. The area refers to the length multiplied by the width of the aluminum plate. Assuming the length and width of the aluminum plate are both 1 meter, then the area is 1 square meter. The thickness of the aluminum plate is 3.175 millimeters and the density is 2.8. Therefore, the weight of the aluminum plate is Weight = 1 square meter x 3.175 millimeters x 2.8 = 8.89 kilograms.
The weight of an aluminum plate will vary with changes in length and width, as these changes will affect the area of the aluminum plate. According to the above formula, the larger the area of the aluminum plate, the heavier it will be.
The thickness of the aluminum plate will also affect 1/8 aluminum plate weight. Generally, a thicker aluminum plate will be heavier. However, the density of the aluminum plate is also a factor that affects its weight. A higher density aluminum plate will be heavier for the same thickness.